Sunday, April 24, 2005

Trig Identities

This is a simple trick that helps me remember a number of useful trig identities in one derivation. We'll derive formulas for both cos(A+B) and sin(A+B) at the same time. First we'll derive a useful relationship between the exponential function, sine and cosine. The Taylor expansion of a function is

doublesincos01

So the Taylor expansion of the the exponential function is

doublesincos02

And the Taylor expansion of sine and cosine are

doublesincos03

and

doublesincos04

Now, expanding the exponential function of i (a square root of -1) times a number theta gives

doublesincos05

So, now we'll use the fact that the product of two exponentials is the exponential of the sum of their powers to give

doublesincos06

Now given that the real parts of both sides must be equal, as well as the imaginary parts, this one equation yields the following two identities

doublesincos07

and

doublesincos08

And that wraps her all up. Now you can easily derive cos(2A) and sin(2A) (the double angle identities) by plugging in A for B in the above equations. Similarly, you can derive sin(A-B) and cos(A-B) by substituting -B for B, and remembering that sin(-x) = -sin(x) and cos(-x) = cos(x).

2 comments:

  1. love the blog man!
    im in A levels, and although some stuff is abit out of my syllabus, its 10x more interesting!
    keep it up, know people like it

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  2. Cool use of power series. My complex analysis professor stressed their usage a lot, and they really are the cornerstone to several topics. I have an example of how to prove power reducing identities using Euler's formula. The technique may prove useful for other derivations as well.
    http://www.natenewz.com/2009/12/16/eulers-identity-and-trig-identities/

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