Next, we'll show that the dot product of two vectors is the product of their lengths and the cosine of the angle between them.
First consider two arbitrary vectors A and B. We'll form a triangle with these two sides and a third side connecting the ends of A and B, which we'll call C. Also, let θ be the angle between sides A and B
Notice that C = A - B, and so
These simplifications rely on properties of the dot product that I worked out last week. Also, since the dot product of a vector with itself is equal to its squared length, we have
and according to the Law of Cosines
Combining these two we can see that
Really.
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